h = int(input())
s = h
for i in range(2, 11):
    s += h
    h /= 2
print(f'{s:.6g}')
print(f'{h/2:.6g}')

#include<cstdio>
using namespace std;
int main(){
	double h; int i=1;
	scanf("%lf",&h);
	double s=h;
	do
	{
		h/=2;
		s+=h*2;
		++i;
	}while(i<=9);
	printf("%g\n%g",s,h/2);
	return 0;
}

提示：输出时不需要对精度特殊控制，用cout << ANSWER，或者printf("%g",ANSWER)即可。